12n^2-52n+48=0

Solution for 12n^2-52n+48=0 equation:

12n^2-52n+48=0

a = 12; b = -52; c = +48;
Δ = b2-4ac
Δ = -522-4·12·48
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-20}{2*12}=\frac{32}{24}
=1+1/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+20}{2*12}=\frac{72}{24}
=3
$